f(x)=2x^3-3x^2+3x-2

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Solution for f(x)=2x^3-3x^2+3x-2 equation: 


Simplifying
f(x) = 2x3 + -3x2 + 3x + -2

Multiply f * x
fx = 2x3 + -3x2 + 3x + -2

Reorder the terms:
fx = -2 + 3x + -3x2 + 2x3

Solving
fx = -2 + 3x + -3x2 + 2x3

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Divide each side by 'x'.
f = -2x-1 + 3 + -3x + 2x2

Simplifying
f = -2x-1 + 3 + -3x + 2x2

Reorder the terms:
f = 3 + -2x-1 + -3x + 2x2

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